By A. Bak
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Extra info for Algebraic K-Theory, Number Theory, Geometry, and Analysis: Proceedings
In many storage scenarios, the only problems relate to key storage, and so, in some of these scenarios, the one-time pad may be as viable as any other cipher. 2007 12:51:11] Chapter 5: Modern Algorithms Team-Fly Chapter 5: Modern Algorithms Introduction Throughout Chapter 3 we stressed that the examples given were not indicative of current practice and that modern encryption algorithms tend to operate on bits rather than the letter substitutions of our examples. In this chapter we discuss modern algorithms.
Since the key is 5 the first step involves writing the message in rows of 5 letters. This is: WHATW ASTHE WEATH ERLIK EONFR IDAY Since the length of the message is not a multiple of 5, we must add one Z to get: WHATW ASTHE WEATH ERLIK EONFRIDAYZ We now read down each column in turn to get the following cryptogram: WAWEEIHSERODATALNATHUFYWEHKRZ To obtain the decryption key we merely divide the length of the message by the key. In this case we divide 30 by 5 to get 6. The deciphering algorithm is then identical to encryption.
These keys are chosen so that it is practically impossible to deduce the private key from the public key. Anyone wishing to use this system to send a secret message to someone else needs to obtain that person's public key and use it to encrypt the data. It is, of course, necessary that they have confidence that they are using the correct public key because, otherwise, it is the owner of the private key corresponding to the public key used, as opposed to the intended recipient, who can understand the message.
Algebraic K-Theory, Number Theory, Geometry, and Analysis: Proceedings by A. Bak